Cím: Dániel Arany Competition in Mathematics, 2001/2002
Füzet: 2003/októberi melléklet, 19 - 21. oldal  PDF  |  MathML 
Témakör(ök): Arany Dániel

A szöveg csak Firefox böngészőben jelenik meg helyesen. Használja a fenti PDF file-ra mutató link-et a letöltésre.

Second round
 

1. Solve the following simultaneous equations on the set of integers:
ab+cd=-1ac+bd=-1ad+bc=-1
 

2. In a right-angled triangle of legs a and b, the altitude drawn to the hypotenuse equals one fourth of the hypotenuse. Evaluate
(ab)6+(ba)6.
 

3. Prove that if
1a+1b+1c=1a+b+c
for the real numbers a, b, c then
1a1001+1b1001+1c1001=1a1001+b1001+c1001.
 

4. The diagonals AC and BD of a convex quadrilateral ABCD are perpendicular. From the midpoint K of side AB, drop a perpendicular onto the line of side DC. Let P denote the foot of the perpendicular. From the midpoint L of side AD, drop a perpendicular onto the line of side BC and denote its foot by Q. Prove that the lines KP and LQ intersect on the line of diagonal AC.
 
Third round (final)
 

1. How many n-digit positive integers are there (in base 10), the sum of whose digits is n3-40, where n is a positive integer?
 

2. In a triangle ABC, BC<CA<AB. The perpendicular bisectors of side BC and side AC intersect the line of the altitude drawn from vertex C at the points P and Q, respectively. Determine the largest angle of the triangle, given that 4CPCQ=AB2.
 

3. Consider the sequence 1,2,3,...,2002. One may rearrange the sequence as follows: It is allowed to put the last number in any of the 1st, 2nd, 3rd, ..., 2002nd places, provided that the number moved forward from the end never precedes a greater number than itself. The same procedure can be applied to the new sequence and repeated as long as it is possible. Prove that after each step, one of the (2k-1)th and the 2kth terms of the sequence thus obtained will be even and the other will be odd, for all 1k1001.
 
Schools with advanced mathematics programme
 
First round
 

1. Prove that if
1a+1b+1c=1a+b+c
for the real numbers a, b, c then
1a1001+1b1001+1c1001=1a1001+b1001+c1001.
 

2. A square of side a is rotated about its centre, and thus a new square is obtained. The common part of the two squares is an equilateral octagon of side b.
a) Express the area of the octagon in terms of a and b.
b) Prove that
tT<a2<t2+T22
where t and T denote the areas of the intersection and union of the two squares, respectively.
 

3. The lines of the sides of an equilateral triangle ABC in the interior of a circle k intersect the circle at the points A1, A2, B1, B2, C1, C2 as follows: The intersections of line AB with the circle are A1 and B2, the intersections of BC are B1 and C2, and the intersections of CA are C1 and A2, as shown in the Figure.
 

Prove that
AA1+BB1+CC1=AA2+BB2+CC2.
 

4. Given that the sum of 121 positive integers is 360, prove that it is possible to select some numbers out of the 121, such that their sum is 120.
 
Second (final) round
 

1. Prove that no matter what positive integer the base of the number system is, it is always true that if the ratio of the number abc¯ to cba¯ is 2 then a+c=b.
 

2. P is a point inside or on the boundary of a regular polygon with 2k+1 sides. Let
d1d2...d2k+1
denote the distances of P from the vertices, in increasing order. For what point will dk+1 be a maximum?
 

3. N microchips can test one another as follows: If any two are connected, each of them will display whether the other is good or faulty. A good chip will always answer correctly while a faulty chip will give a random answer. Given that more than half of the chips are good, is it possible to select a good chip with certainty in less than N trials?